Re: [xsl] group by number

[Frederic Laurent <fl@xxxxxxxxxxxxx>]

Andreas Lindahl wrote:

> Hi
> 
> I have an xml file which looks pretty much like this:
> 
<snip/>

> Each group node should contain three item nodes.
> 
> How should I do this with XSLT?

use the position function...
I set the root node to result


<xsl:template match="/">
<result>
  <xsl:apply-templates select="//item" mode="test"/>
</result>
</xsl:template>

<xsl:template match="item" mode="test">
  <xsl:if test="position() mod 3 = 1">
    <group id="{ceiling(position() div 3)}">
      <xsl:apply-templates select="."/>
      <xsl:apply-templates select="following-sibling::item[1]"/>
      <xsl:apply-templates select="following-sibling::item[2]"/>
   </group>
  </xsl:if>
</xsl:template>


<xsl:template match="item">
  <xsl:copy><xsl:apply-templates select="*|@*|text()"/></xsl:copy>
</xsl:template>

----

java org.apache.xalan.xslt.Process -IN items.xml -XSL items.xsl
<?xml version="1.0" encoding="UTF-8"?>
<result>
<group id="1">
<item>1</item>
<item>2</item>
<item>3</item>
</group>
<group id="2">
<item>4</item>
<item>5</item>
<item>6</item>
</group>
<group id="3">
<item>7</item>
<item>8</item>
<item>9</item>
</group>
</result>


HTH

cheers

-- 

XPath free testing software :  http://lantern.sourceforge.net
Frédéric Laurent                     http://www.opikanoba.org

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