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Subject: [xsl] HOWTO: convert flat list w/ level information to a hierarchial one? From: "Marcus Zelezny" <Marcus.Zelezny@xxxxxx> Date: Tue, 2 Dec 2003 11:40:58 +0100 |
Dear XSLT Community!
I couldn't solve a problem of class "flat file transform".
>From (@name, just for illustration) flat file with @level information:
<node>
<node level="0" type="c" name="toplevel"/>
<node level="1" type="i" name="1. item"/>
<node level="1" type="c" name="2. container"/>
<node level="2" type="i" name="2.1 item"/>
<node level="2" type="i" name="2.2 item"/>
<node level="1" type="i" name="3. item"/><!-- implicit close of previous container -->
<node level="1" type="c" name="4. container"/>
<node level="2" type="i" name="4.1 item"/>
<node level="2" type="c" name="4.2 container"/>
<node level="3" type="i" name="4.2.1 item"/>
</node>
<!--
@type = 'c' ... container
@type = 'i' ... Item
-->
transform to:
<node>
<node type="c" name="toplevel">
<node type="i" name="1. item"/>
<node type="c" name="2. container"/>
<node type="i" name="2.1 item"/>
<node type="i" name="2.2 item"/>
</node>
<node type="i" name="3. item"/>
<node type="c" name="4. container">
<node type="i" name="4.1 item"/>
<node type="c" name="4.2 container"/>
<node type="i" name="4.2.1 item"/>
</node>
</node>
</node>
</node>
What I tried:
Calling recursively a template with passing parameters $node, $last-level, but I failed to leave recursion in a proper way;-(
Any pointer|hint|solution for a (ideally) XSLT1.0 approach is highly appreciated!
Thanks in advance
Marcus
P.S. I read http://www.dpawson.co.uk/xsl/sect2/flatfile.html
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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