Re: [xsl] Checking element to see if it has children...

[JCS <subscriber@xxxxxxxxxxxxx>]

Hi Jarno,

Thanks for the response. I did check the FAQ again under "Empty Elements" to
see about element checking. I think I ran into one those XSL "snafus"
because when I ran a test to see if elements didn't have children, I didn't
get any output when selecting ancestor::* (just the tests for "yes" came
through). My head is still having a little trouble with this...

But using the following stylesheet & data:

-------------------
<xsl:template match="/">

    <xsl:for-each select="/*//*">
        <xsl:call-template name="path"/>
    </xsl:for-each>
 
</xsl:template>  

<xsl:template name="path">

<!--this is selecting the ancestors of current node-->
<xsl:for-each select="ancestor::*">
    <xsl:choose>
          <xsl:when test="not(node())">
        Not node: <xsl:value-of select="name()"/> has no children:
          </xsl:when>
          <xsl:when test="node()">
            <font color="blue">
                <xsl:value-of select="name()"/>
        </font>    
          </xsl:when>
    </xsl:choose>
    <xsl:text>/</xsl:text>
</xsl:for-each>

    <font color="red">
        <xsl:value-of select="name()"/>
    </font> 
<br/>
</xsl:template>  

</xsl:stylesheet> 

----------

<root>
<element_one>one</element_one>
<element_two>two</element_two>
<element_three>thing</element_three>
<element_four>
    <element_four_one>
    </element_four_one>
</element_four>
</root>

------------

I get the following:

root /element_one 
root /element_two 
root /element_three
root /element_four 
root /element_four /element_four_one



But I would like the output to be:

root /element_one 
root /element_two 
root /element_three
root /element_four /element_four_one

Because ³element_four² is a container and has no text, it shouldn¹t be a red
³stub².

Also, I tried running this template on a 1MB file, just to prove I¹m related
to Forrest Gump, and it took over three minutes to process. So I¹m imagining
that I could use a key in here to speed up the process. Then there¹s that
lovely part about removing duplicates once the pattern repeats itself...

/johnny :)


On 10/12/03 1:30 AM, "Jarno.Elovirta@xxxxxxxxx" <Jarno.Elovirta@xxxxxxxxx>
wrote:

> FAQ,
> 
>> For starters I've been trying to figure out how to check to see if an
>> element contains elements (has child element nodes) but I'm--stumped.
> 
> Try to select it
> 
> <xsl:if test="*">
>   ...
> </xsl:if>
> 
> Cheers,
> 
> Jarno - Blank: Overhead (Extended)
> 
> XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 
> 
> 

-- 
The aging process has you firmly in its grasp if you never get the urge to
throw a snowball. 
-- Doug Larson 


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list