RE: [xsl] Getting a distinct list of node names

["Andreas L. Delmelle" <a_l.delmelle@xxxxxxxxxx>]

> -----Original Message-----
> From: Manuel Holtgrewe
>
> I need to get a distinct list of the node names from all children of one
> node. For example, if I have:
>
>     <node:definition>
>         <form:validator />
>         <form:validator />
>         <form:filter />
>     </node:definition>
>

tricky one...

I tried it like:

<xsl:template match="node:definition">

  <xsl:for-each select="*[name(.) != preceding::*]">
    <xsl:if test="position() = 1">
      <xsl:text>('</xsl:text>
    </xsl:if>
    <xsl:value-of select="name()" />
    <xsl:text>'</xsl:text>
    <xsl:choose>
      <xsl:when test="position() != last()">
        <xsl:text>, </xsl:text>
      </xsl:when>
      <xsl:otherwise>
        <xsl:text>)</xsl:text>
      </xsl:otherwise>
    </xsl:choose>
  </xsl:for-each>

</xsl:template>

Provided you include the namespace declaration for the node:* namespace in
your XSL, there shouldn't be any problems... Could get expensive with long
lists maybe.


Cheers,

Andreas


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