RE: [xsl] getting all parent elements for breadcrumb nav

Subject: RE: [xsl] getting all parent elements for breadcrumb nav
From: Nathan Shaw <n8_shaw@xxxxxxxxx>
Date: Tue, 16 Dec 2003 11:35:52 -0800 (PST)
Doh! Thinking too hard I guess =;>

Thanks!



--- Jarno.Elovirta@xxxxxxxxx wrote:
> FAQ,
> 
> > I am working on an application that uses the xbel
> dtd
> > for a set of bookmarks. In the xslt I am writing,
> I
> > want to create a breadcrumb navigation item at the
> top
> > so that the user can walk up and down the folders.
> I
> > pass in a folderID in the xml so that I can show
> the
> > proper folder and need to somehow grab all of that
> > folder's parent elements and put them into a
> > breadcrumb navigation line (Top folder > sub
> folder >
> > sub folder).
> 
>   <xsl:for-each select="ancestor::folder">
>     <xsl:value-of select="title"/>
>     <xsl:text> &gt; </xsl:text>
>   </xsl:for-each>
> 
> when bookmark is the current node.
> 
> Cheers,
> 
> Jarno
> 
>  XSL-List info and archive: 
> http://www.mulberrytech.com/xsl/xsl-list
> 


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