Subject: RE: [xsl] getting all parent elements for breadcrumb nav From: Nathan Shaw <n8_shaw@xxxxxxxxx> Date: Tue, 16 Dec 2003 11:35:52 -0800 (PST) |
Doh! Thinking too hard I guess =;> Thanks! --- Jarno.Elovirta@xxxxxxxxx wrote: > FAQ, > > > I am working on an application that uses the xbel > dtd > > for a set of bookmarks. In the xslt I am writing, > I > > want to create a breadcrumb navigation item at the > top > > so that the user can walk up and down the folders. > I > > pass in a folderID in the xml so that I can show > the > > proper folder and need to somehow grab all of that > > folder's parent elements and put them into a > > breadcrumb navigation line (Top folder > sub > folder > > > sub folder). > > <xsl:for-each select="ancestor::folder"> > <xsl:value-of select="title"/> > <xsl:text> > </xsl:text> > </xsl:for-each> > > when bookmark is the current node. > > Cheers, > > Jarno > > XSL-List info and archive: > http://www.mulberrytech.com/xsl/xsl-list > __________________________________ Do you Yahoo!? New Yahoo! Photos - easier uploading and sharing. http://photos.yahoo.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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