Subject: [xsl] Re: variable indirection From: "Dimitre Novatchev" <dnovatchev@xxxxxxxxx> Date: Sun, 28 Dec 2003 18:26:52 +0100 |
<karim@xxxxxxxxxxxxxxxx> wrote in message news:1072588445.3fee669d6e86e@xxxxxxxxxxxxxxx > > Hi, > > Here's what I want to do : > In a template I've got a variable which value is a string, this string is also > the name of a variable and I want to access it > For example : > $var1="var2" and I want to get $var2... > Is that possible with xsl? Generally no. Exceptions: 1. A global xsl:variable with *static* content: document('')/*/xsl:variable[@name = $var1]/@select 2. If the content of your variable is created dynamically, you can express this with the following dynamically created xml: <varContainer:varContainer xmlns:varContainer="my:varContainer"> <varName1>tree1</varName1> <varName2>tree2</varName2> . . . . . . . . . . . . . . . . . . <varNameN>treeN</varNameN> </varContainer:varContainer> Then, if the above is the contents of the xsl:variable named "vContainer", what you want is: $vContainer/*[name() = $var1]/node() There's little meaning in your question as originally formulated, as typically compiled languages (e.g. C, C++, Java, C#, etc.) do not allow referencing a variable with dynamically created name. Some of them have a pre-processor for this, but its work is done even before compile-time. Dimitre Novatchev. FXSL developer http://fxsl.sourceforge.net/ -- the home of FXSL Resume: http://fxsl.sf.net/DNovatchev/Resume/Res.html XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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