Re: [xsl] Re for-each identifying current iteration

["Skwirel Software Ltd" <mark@xxxxxxxxxxx>]

Thanks guys.

Mark

----- Original Message -----
From: "Thomas Rasmussen" <tbr77@xxxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Monday, December 29, 2003 6:33 PM
Subject: Re: [xsl] Re for-each identifying current iteration


> Mark Williams wrote:
>
> >Hi,
> >
> >I'm sure there is an incredibly easy way of doing this, but as usual I
can't
> >find it!
> >
> >During a for-each iteration how do you identify what is the integer value
of
> >the current iteration.
> >
> >Thanks
> >
> >Mark Williams
> >
> >
> > XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> >
> >
> >
> >
> Hello
>
> I think position() could do the job:
> #xsl
> <xsl:template match="/">
>       <xsl:for-each select="/root/node">
>         <xsl:value-of select="position()"/>
>       </xsl:for-each>
> </xsl:template>
> # xml-file
> <root>
> <node/>
> <node/>
> </root>
>
> Regards
> ThomasRasmussen
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list