Subject: Re: [xsl] sorting information from multiple files From: "james walker" <jameswalkerandy@xxxxxxxxxxx> Date: Mon, 19 Jan 2004 14:00:04 +0000 |
From: David Carlisle <davidc@xxxxxxxxx> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] sorting information from multiple files Date: Thu, 15 Jan 2004 16:23:03 GMT
document() will accept a node set rather than a string so if it wasn't for the " " "-" translation you could replace
<xsl:for-each select="child::category"> <xsl:variable name="catnamemod" select="translate(name,' ','_')" /> <xsl:for-each select="document($nsindex/*[name()=$catnamemod])/root/child::*"> <xsl:if test="@topfive=true()">
by
<xsl:for-each select="document($nsindex/*[name()=current()/category/name])/root/child::*[@topfive]">
Is it not possible to arrange that your nsindex variable has the right names
(by doing the translation at the point you construct that variable?
it's inconvenient to do the translation later as that is a string based function which stops you using the implicit existential quantification over a node set that you get with =.
-- http://www.dcarlisle.demon.co.uk/matthew
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