Subject: [xsl] Sorting Issue From: "SHEIKH Sajjad" <Sajjad.SHEIKH@xxxxxxxxxxx> Date: Wed, 21 Jan 2004 15:56:53 +0100 |
Hi all, Following style sheet processes multiple xml documents (lets say file1.xml, file5.xml and file8.xml). It will sort all the results by modificationDate seperately and will output the results as following. link1 021203 (From File1) link2 011203 (From File1) link3 101103 (From File5) link4 031203 (From File8) link5 091103 (From File8) I want to sort everything together. For example, link4 031203 (From File8) link1 021203 (From File1) link2 011203 (From File1) link3 101103 (From File5) link5 091103 (From File8) Any suggestions? Regards, /s <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <xsl:apply-templates select="/someURIs/file"/> </xsl:template> <xsl:template match="file"> <xsl:variable name="copy_current_file" select="document(string(.))"/> <table><xsl:apply-templates select="$copy_current_file/ll"/></table> </xsl:template> <xsl:template match="ll"> <xsl:variable name="find_file"> <xsl:for-each select="loc"> <xsl:if test="position()=last()-1">(From <b><xsl:value-of select="."/></b>)</xsl:if> </xsl:for-each> </xsl:variable> <xsl:for-each select="*//lln"> <xsl:sort select="@modificationDate" order="descending"/> <xsl:choose> <xsl:when test="@objectname='Folder'"> <tr> <td> <a href="{@docname}/l.shtml"> <xsl:value-of select="n/@docname"/> </a> </td> <td> <xsl:value-of select="@identity"/> </td> <td> <xsl:value-of select="@modificationDate"/> </td> <td><xsl:value-of select="$find_file"/></td> </tr> </xsl:when> </xsl:choose> </xsl:for-each> </xsl:template> </xsl:stylesheet> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] working out the xsl docum, J.Pietschmann | Thread | RE: [xsl] Sorting Issue, SHEIKH Sajjad |
Re: [xsl] Select elements between o, Joe Fawcett | Date | RE: [xsl] Using keys to filter node, Amuchastegui, Maria |
Month |