Subject: RE: [xsl] template matching From: cknell@xxxxxxxxxx Date: Wed, 04 Feb 2004 09:45:06 -0500 |
If your sample actually represents your input, you could create a template that matches a node based on a substring of the node's name. <xsl:template match="*[substring(name(),1,3)='sub']"> <ul> <xsl:apply-templates select="note" /> </ul> </xsl:template> Of course, if your element names have nothing in common that can be described with substring(), you will have to make one template for each. -- Charles Knell cknell@xxxxxxxxxx - email -----Original Message----- From: james walker <jameswalkerandy@xxxxxxxxxxx> Sent: Wed, 04 Feb 2004 13:26:30 +0000 To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] template matching if i have a note elemtn that can be placed in side many different elements within an xml document e.g. <main> <sub1><note></note><note></note><note></note></sub1> <sub2></sub2> <sub3><note></note></sub3> <sub4><note></note><note></note><note></note><note></note></sub4> <sub5></sub5> </main> If i wanted to produce a list of notes when the note element appears i would do something like this: <xsl:template match="sub1"> <ul> <xsl:apply-templates select="note" /> </ul> </xsl:template> <xsl:template match="sub3"> <xsl:template match="sub4"> </xsl:template> <xsl:template match="note"> <li><xsl:value-of select="note" /></li> </xsl:template> Is there anyway i can reduce this code down because i have this implemented on a much larger scale where the note element appears within 28-30 other elements. Is there anyway to reproduce the output which the design above creates without having to write out <ul> tags within each template match? cheers james _________________________________________________________________ Express yourself with cool new emoticons http://www.msn.co.uk/specials/myemo XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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