RE: [xsl] Apply Template based on position or count

["Kenny Akridge" <kakridge@xxxxxxxxxxxxx>]

I'm not exactly certain what you are trying to do, but if you want two
columns, you'll need to do something like this:

 <table width="200" border="1">
  <xsl:for-each select="//z:row">
        <xsl:if test="position() mod 2 = 1">
     <tr/>
         <td valign="top"><xsl:apply-templates select="."
mode="session_info"/></td>
            <td valign="top"><xsl:apply-templates select="."
mode="session_info"/></td>
        </xsl:if>
		        <xsl:if test="position() mod 2 = 0">
     
         <td valign="top"><xsl:apply-templates select="."
mode="session_info"/></td>
            <td valign="top"><xsl:apply-templates select="."
mode="session_info"/></td>
		<tr/>
        </xsl:for-each>
	
    </table>

Notic:  the second select is "."  How do i get the next z:row?

>>> The next z:row will be given to you in the for-each loop.  
>>> Maybe some sample xml and a simple drawing will help.

Karl


----- Original Message -----
From: "Karl J. Stubsjoen" <karl@xxxxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Thursday, February 05, 2004 6:25 PM
Subject: [xsl] Apply Template based on position or count


> Hi there,
>
> I have a node fragment with (lets say) 20 items in it.  I would like
to
> apply a template rule which matches the first 10 nodes, and then later
the
> 2nd ten.  Ultimately I am trying to create two columns in my html
output.
> Now, lets say there are 25 items, so the first set would contain 13
items
> and the 2nd set 12 items - but somehow in XSLT no that we need to
match 13
> rows on the left so add 1 more row.
>
> So, can you apply-templates and specify some sort of [1-10] match?
>
> Karl
>
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>
>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list