Re: [xsl] Selecting and printing certain nodes

["Glenn MacGregor" <gtm@xxxxxxxxxxxxxxxxxxxxxx>]

Thanks a million! Works great.


----- Original Message -----
From: "David Carlisle" <davidc@xxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Friday, February 20, 2004 12:06 PM
Subject: Re: [xsl] Selecting and printing certain nodes


>
> > This prints out '$startDate' when I really want it to print the value of
the
> > xsl:param $startDate. Is there a way to do this in XSL?
>
> No, you can't refer to the program variables from the source file unless
> you have an extension element that makes an XPath parser available at
> run time some systems do (saxon for example) but not all of them make
> variable bindings available to the run time extension function.
>
> ah I see you already are using dyn:evaluate so in that case you could
> probably evaluate the string "$startDate" coming from the source.
> But do you really want to polute your source files with the internal
> variables used in the stylesheet. You wouldn't normally expect a file
> read in to a compiled C program (say) to access the variables used in
> that program, it's rather similar here.
>
>
> Incidentally there is no need to have the if in
>
>    <xsl:if test="@name"/>
>         <xsl:value-of select="@name"/>
>     </xsl:if>
>
> if the attribute isn't there it's value will be "".
>
>   This all work great. Now my question is can you think of a way to handle
>   nested foreach statments?
>
> it'll just work automatically due to the nested apply-templates, won't
> it? I can't see any reason why not.
>
>
>   Do I need to pass a variable which is an array or something
>
> XSLT doesn't have arrays, it  has node sets which are just as useful,
> but I don't see that you have pass anything other than your existing
> item node.
>
> David
>
>
> --
> http://www.dcarlisle.demon.co.uk/matthew
>
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