[xsl] Network diagram - node set intersection

Subject: [xsl] Network diagram - node set intersection
From: cknell@xxxxxxxxxx
Date: Mon, 23 Feb 2004 12:34:53 -0500
==========> Direction of graph
            |        |
          / |__B__|
______/	          \_____
|        |	          |        |
|__A__|	          |__D__|
          \	           /
           \ ______/
           |        |

I'm working on producing a network diagram in SVG by processing an XML document with XSLT. Above is a symbolic representation of the output. The relationship between nodes in the graph can't be represented directly in XML because it isn't a tree (Node D has two parents which isn't allowed in XML).

Here is a simplified sample of the XML document:

In my stylesheet I have a template that matches <node>. For the purpose of positioning the SVG elements I want to determine how many other nodes have a <predecessor-id> that matches one of the <predecessor-id> children of the context <node>. In addition to determining how many "siblings" a <node> has, I also want to know where the context node is in document order relation to these "siblings".

The <node> elements with common <predecessor-id> values would be, in the context of the network diagram, "siblings". Of course in the XML document all the <node> elements are siblings in the XPath sense.

To determine the number of siblings a <node> element has, I thought I would count the elements in the intersection of the set of <predecessor-id> children of the context node with the set of <predecessor-id> children of all the other <node> elements. I modelled the expression on the example shown on page 425 of the XSLT Programmer's Reference 2nd Edition.

Here is a simplfied stylesheet:

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
  <xsl:output method="xml" indent="yes" encoding="UTF-8" />

  <xsl:template match="/">
    <xsl:apply-templates />

  <xsl:template match="network">
    <xsl:apply-templates />

  <xsl:template match="node">
    <xsl:variable name="this-node-id" select="node-id" />
    <xsl:variable name="this-predecessor-nodes" select="predecessor-id" />
    <xsl:variable name="other-predecessor-nodes" select="/network/node[node-id != $this-node-id]" />
    <xsl:variable name="sibling-cnt" select="count($this-predecessor-nodes[count(. | $other-predecessor-nodes) != count($other-predecessor-nodes)])" />

    This node id = <xsl:value-of select="$this-node-id" />
    Sibling count = <xsl:value-of select="$sibling-cnt" />


This yielded the following output:

<?xml version="1.0" encoding="UTF-8"?>

    This node id = A
    Sibling count = 1

    This node id = B
    Sibling count = 1

    This node id = C
    Sibling count = 1

    This node id = D
    Sibling count = 2

It the intersection operation didn't do what I expected. I expected that nodes A and D would have a Sibling count of 0 and that nodes B and C would each have a sibling count of 1.

Could anyone tell me where I'm going wrong and point me in the right direction?

Charles Knell
cknell@xxxxxxxxxx - email

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