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RE: [xsl] How to output the less-than sign (and not &lt;)

Subject: RE: [xsl] How to output the less-than sign (and not &lt;)
From: "Andreas L. Delmelle" <a_l.delmelle@xxxxxxxxxx>
Date: Mon, 1 Mar 2004 19:39:12 +0100
> -----Original Message-----
> From: Amuchastegui, Maria
>
> I am trying to generate HTML which contains an embedded
> hyperlink. However,
> because I use &lt; as the start tag, the resulting HTML displays
> the actual
> source code, and not a hyperlink. How do I escape the escape character so
> that the HTML contains the less-than sign?
>

Hi,

Is there any reason in particular why you can't do, for instance :

<xsl:template match="???">

  <xsl:text>Upon pressing submit you are agreeing to the Terms and
Conditions on </xsl:text>
  <a href="http://www.bell.ca"; target="newwindow">bell.ca</a>
  <xsl:text> the terms and conditions on Bell's site</xsl:text>

</xsl:template>

?

Remember that the 'tags' are, especially in this case, valid XML, ergo valid
XSLT code.

Hope this helps!

Cheers,

Andreas


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