Re: [xsl] XPath to get value of xmlns attribute

["G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>]

At 2004-03-09 08:19 -0500, Munna D wrote:
> Say I have an xml document beginning as follows:
> ...
> I want to make a list of all atttributes (including namespace declaration 
> ones). However, both of the templates below fail to pick up the xmlns and 
> xmlns:tt attributes:

Correct, because namespace attributes show up on the namespace axis, not on 
the attribute axis.

I hope the example below helps.

.................. Ken

T:\ftemp>type munna.xml
<?xml version="1.0" encoding="utf-8"?>
<!--extract for example-->
<feed version="0.2" xmlns="http://purl.org/atom/ns#";
  xmlns:tt="http://www.tt.org/ns#"/>
<!--end of extract-->

T:\ftemp>type munna.xsl
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
                version="1.0">

<xsl:output method="text"/>

<xsl:template match="*">
  <xsl:for-each select="namespace::node()">
    The prefix: <xsl:value-of select="name(.)"/>
    The URI:    <xsl:value-of select="."/>
  </xsl:for-each>
</xsl:template>

</xsl:stylesheet>
T:\ftemp>saxon munna.xml munna.xsl

    The prefix: xml
    The URI:    http://www.w3.org/XML/1998/namespace
    The prefix:
    The URI:    http://purl.org/atom/ns#
    The prefix: tt
    The URI:    http://www.tt.org/ns#
T:\ftemp>




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