Subject: RE: [xsl] xsl:if statement with numeric From: "Tuan Luu" <tuanluu@xxxxxx> Date: Sun, 28 Mar 2004 12:47:18 +0200 (MEST) |
Hallo Andreas Thank you very much for your kind answer. That was a great idea and I like you're solution. have a nice day Tuan > > -----Original Message----- > > From: Tuan Luu [mailto:tuanluu@xxxxxx] > > > > somehow I did find a solution: > > > > Hi, > > Well, to add a few pointers : > > > > > > > <xsl:template match="monat"> > > > <xsl:if test= "numeric(.) < 100.00"> > > This should be number() instead of numeric(), but this you already > discovered.. > > > > <xsl:variable name="farbe">#00ff00</xsl:variable> > > > </xsl:if> > > > <td bgcolor="$farbe" align="right"> > > Then this here should become: > > <td bgcolor="{$farbe}" align="right"> > > Notice the curly braces {} to force the processor to interpret '$farbe' as > a > variable name, or more generally as an XPath expression. > > Somehow, I would consider putting a color-map somewhere in the source XML, > the stylesheet or a separate XML, like: > > <colormap> > <color min="0" color="#ff9600" /> > <color min="98.70" color="#ff0000" /> > <color min="100" color="#00ff00" /> > </colormap> > > Then you could avoid all the xsl:choose / xsl:if logic by merely fetching > the color value corresponding to the number value in question, like > > <xsl:template match="monat"> > <td bgcolor="{/colormap/color[@min >= number(current())][1]/@color}" > align="right"> > ... > > So, fetch the color attribute from the first color node whose min value is > greater than or equal to the current value. > > > Hope this helps! > > Cheers, > > Andreas > -- +++ NEU bei GMX und erstmalig in Deutschland: T\V-gepr|fter Virenschutz +++ 100% Virenerkennung nach Wildlist. Infos: http://www.gmx.net/virenschutz
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