Subject: RE: [xsl] Getting the first and last nodes of a sorted nodeset From: "Hansen, John" <John.Hansen@xxxxxxxxxx> Date: Fri, 9 Apr 2004 09:28:35 -0700 |
Thanks, Wendell, for the information about binding a variable to the sorted result tree fragment. Since my friend's need was to grab the earliest and latest dates and the dates are guaranteed to be 10 characters long (2004-01-31) he can use a much simpler approach than I sent him previously: <xsl:stylesheet xmlns:xsl='http://www.w3.org/1999/XSL/Transform' version='1.0'> <xsl:output method='html'/> <xsl:template match="/root"> <html> <xsl:variable name="ND"> <xsl:apply-templates select="//nd"> <xsl:sort/> </xsl:apply-templates> </xsl:variable> <xsl:call-template name="test_template"> <xsl:with-param name="b"><xsl:value-of select="substring($ND, 1, 10)"/></xsl:with-param> <!-- earliest date --> <xsl:with-param name="c"><xsl:value-of select="substring($ND, string-length($ND)-9, 10)"/></xsl:with-param> <!-- latest date --> </xsl:call-template> </html> </xsl:template> <xsl:template name="test_template"> <xsl:param name="b"></xsl:param> <xsl:param name="c"></xsl:param> <xsl:value-of select="$b" /><br/> <xsl:value-of select="$c" /> </xsl:template> </xsl:stylesheet>
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