Subject: RE: [xsl] How to convert flat data to hierarchical data From: "Andreas L. Delmelle" <a_l.delmelle@xxxxxxxxxx> Date: Mon, 26 Apr 2004 19:24:20 +0200 |
> -----Original Message----- > From: Hansen, John [mailto:John.Hansen@xxxxxxxxxx] > > Is there a simple stylesheet that will transform the flat data shown > below into the hierarchical form that is at the end of this email? I Hi, Depends on what you call simple, doesn't it? I'd suggest something like: <xsl:stylesheet ...> <xsl:key name="by-parent" match="EmployeeGroup" use="Parent/@SK" /> <xsl:template match="/"> <xsl:apply-templates select="EmployeeGroup[not(Parent/@SK)]" /> </xsl:template> <xsl:template match="EmployeeGroup"> <xsl:copy> <xsl:copy-of select="@*" /> <xsl:copy-of select="*[not(name()='Parent')]" /> <xsl:apply-templates select="key('by-parent',@SK)" /> </xsl:copy> </xsl:template> </xsl:stylesheet> Beware though: untested. HTH! Cheers, Andreas
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] How to convert flat data to h, Hansen, John | Thread | RE: [xsl] How to convert flat data , Michael Kay |
[xsl] How to convert flat data to h, Hansen, John | Date | [xsl] ANN: Syntext Serna V1.5: XSL-, xsl-list |
Month |