Subject: [xsl] Xpath of an attribute From: "Animesh Sharma" <asharma@xxxxxxxxxxxxxxxx> Date: Tue, 27 Apr 2004 14:17:55 +0530 |
hi, I want to remove a particular attribute of node. Is there way that I can write the template in one line something like: <xsl:template match="//body/namespace/form/snip/csf/div/center/p[position()=1]/a[position()=1][@href]"/> <xsl:template match="*|text()|@*"> <xsl:copy> <xsl:apply-templates select="*|text()|@*"/> </xsl:copy> </xsl:template> This removes the anchor element.. but I just want to remove the "href" attribute of element. Regards, Animesh
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