Re: [xsl] Retrieving the position of an ancestor in nested <xsl:for-each>

[David Carlisle <davidc@xxxxxxxxx>]

   <xsl:for-each select="Node">
	   ...
<xsl:variable name="x" select="position()"/>
	   <xsl:for-each select="SubNode">
		   Position of Node: <xsl:value-of select="??????????"/> <!-- How will I get 
                        the position of the anchestor -->
<xsl:value-of select="$x"/>

David


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