Subject: Re: [xsl] Retrieving the position of an ancestor in nested <xsl:for-each> From: David Carlisle <davidc@xxxxxxxxx> Date: Tue, 4 May 2004 12:14:21 +0100 |
<xsl:for-each select="Node"> ... <xsl:variable name="x" select="position()"/> <xsl:for-each select="SubNode"> Position of Node: <xsl:value-of select="??????????"/> <!-- How will I get the position of the anchestor --> <xsl:value-of select="$x"/> David -- The LaTeX Companion http://www.awprofessional.com/bookstore/product.asp?isbn=0201362996 http://www.amazon.co.uk/exec/obidos/tg/detail/-/0201362996/202-7257897-0619804 ________________________________________________________________________ This e-mail has been scanned for all viruses by Star Internet. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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