RE: [xsl] Simple XSL but having problems

[vsubramanian@xxxxxxxxxx]

If your desired output is :
<?xml version="1.0" encoding="UTF-8"?>
test1
                    ::
                    test2
                    ;;
            test3
                    ::
                    test4
                    ;;


Then try this
===================

<?xml version='1.0' encoding='utf-8' ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
    <xsl:template match="@*|*">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
    </xsl:template>
    <xsl:template match="a">
      
            <xsl:for-each select="b mod 2">
               
                    
                   <xsl:value-of select="c1"/>
                    ::
                    <xsl:value-of select="c2"/>
                    ;;
            </xsl:for-each>
       
    </xsl:template>    
</xsl:stylesheet>




-----Original Message-----
From: Dylan Barber [mailto:dylan.barber@xxxxxxxxxxxxx]
Sent: Tuesday, May 11, 2004 11:02 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] Simple XSL but having problems


Here is my xml layout

<a>
   <b>
       <c1>test1</c1>
       <c2>test2</c2>
   </b>
   <b>
   <b>
       <c1>test3</c1>
       <c2>test4</c2>
   </b>
</a>

and i want to show c1 and c2 so i have this 

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
	<xsl:template match="/">
			<xsl:for-each select="a/b">
				<xsl:value-of select="c1"/>
				::
				<xsl:value-of select="c2"/>
				;;
			</xsl:for-each>:|*|:
	</xsl:template>
</xsl:stylesheet>  


however all i get is :|*|:

what did i do wrong (please no rebukes I am trying to understand this and I
think this structure should work its easy enough)

Thanks !!!!!

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Dylan Barber                              :  AOL Messenger - dylanbarb
(CIW Professional, A+ Technician): MSN Messenger -
dylan.barber@xxxxxxxxxxxxx
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