|
Subject: RE: [xsl] Small changes to source XML From: "Michael Kay" <mhk@xxxxxxxxx> Date: Fri, 14 May 2004 15:40:18 +0100 |
Write an identity template that copies everything:
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
Then override it for the things you want to change:
<xsl:template match="a/@ID">
<xsl:attribute name="ID">0</xsl:attribute>
</xsl:template>
Michael Kay
> -----Original Message-----
> From: Kenny Akridge [mailto:kenny@xxxxxxxxxxxxxxxxx]
> Sent: 14 May 2004 13:16
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Small changes to source XML
>
> Forgive me for seeming ignorant, but I certainly am in this
> case. I want to
> mostly copy all of my source XML to the output XML, with some
> small changes.
> For instance:
>
> <root>
> <a ID="74">
> <a ID="75">
> <a ID="76">
> </root>
>
> I want this output:
>
> <root>
> <a ID="0">
> <a ID="0">
> <a ID="0">
> </root>
>
>
> What is the best way to do this with a lot of XML without
> using xsl:element?
| Current Thread |
|---|
|
| <- Previous | Index | Next -> |
|---|---|---|
| Re: [xsl] Small changes to source X, G. Ken Holman | Thread | [xsl] xsl:call-template not recogni, Manali Bhole |
| RE: [xsl] Cannot write an attribute, Michael Kay | Date | RE: [xsl] how to figure out what le, Passin, Tom |
| Month |