RE: [xsl] XSLT sort

[Tomas Olsson <tomas.olsson@xxxxxxxxxxxxxxxxxxxxxxxx>]

yes, thats what i wanted. Now I tried a solution like this on a document 
with 8000 lines:

<xsl:key name="name-key" match="Person" use="@enamn" />

<xsl:template match="Katalog">
 <xsl:copy>
  <xsl:variable name="unique-names"
                select="Person[generate-id()=
                  generate-id(key('name-key',@enamn))]/@enamn" />
  <xsl:for-each select="$unique-names">
    <xsl:sort select="." order="ascending" />
    <xsl:apply-templates select="key('name-key',.)" />
  </xsl:for-each>
 </xsl:copy>
</xsl:template>

<xsl:template match="Person">
 <xsl:copy-of select="."/>
</xsl:template>

But I didnt get any better performance. My document is like this:

<Katalog>
  <Person fnamn="Orvar" enamn="Olsson" tfn="026-789536">
    <Adress adress="Norrav. 34" postnr="50623" 
postort="Soderhamn">japp</Adress>
    <Cv>Har arbetat som konsult hos microsoft sedan barnsben</Cv><Info 
alder="24"/>
  </Person>
  <Person fnamn="Orvar" enamn="Orre" tfn="026-782576">
    <Adress adress="Sodrav. 34" postnr="50323" postort="Gavle"/>
    <Cv>Har arbetat som stadare hos ericsson</Cv><Info alder="24"/>
  </Person>
  <Person fnamn="Per" enamn="Olsson" tfn="026-789536">
    <Adress adress="Norrav. 34" postnr="50623" postort="Soderhamn"/>
    <Cv>Sommarjobbat hos prv</Cv><Info alder="24"/>
  </Person>
.
.
.
</Katalog>

And I have a lot of elements with the same "enamn" attribute. Is It 
possible to solve it any other way to get better performance?

/Tomas

At 22:32 2004-05-20 +0200, you wrote:
> > -----Original Message-----
> > From: Tomas Olsson [mailto:tomas.olsson@xxxxxxxxxxxxxxxxxxxxxxxx]
> >
>
> Hi,
>
> > Im trying to get better performance by using keys, I have heard thats
> > possible but I dont know how to do.
> >
>
> Well, depends on what you want to achieve.
>
> Your initial code:
>
> - applies templates to the Person nodes, sorted on @enamn
> - for each Person node, applies templates to the @enamn node
> - for each @enamn (one on each Person node), insert a copy of every Person
> node with an @enamn equal to the current one
>
> Unfortunately, we can only guess what the initial structure is that you're
> trying to improve. My best guess is you want to create a variable containing
> all unique @enamn values in the document, and use that to take control over
> the template matching, like:
>
> <xsl:key name="name-key" match="Person" use="@enamn" />
>
> <xsl:template match="Katalog">
>   <xsl:variable name="unique-names"
>                 select="Person[generate-id()=
>                   generate-id(key('name-key',@enamn))]/@enamn" />
>   <xsl:for-each select="$unique-names">
>     <xsl:sort select="." order="ascending" />
>     <xsl:apply-templates select="key('name-key',.)" />
>   </xsl:for-each>
> </xsl:template>
>
> In this way, the sorting will only be performed on the group of unique names
> instead of on all nodes in the document, which could mean a considerable
> improvement in documents as large as you describe.
>
>
> HTH!
>
> Greetz,
>
> Andreas