RE: [xsl] Using <xsl:number>

[<Jarno.Elovirta@xxxxxxxxx>]

Hi,

> What I want to do is add a sort-order property to each
> Scope tag, which identifies its relative position at
> each level of the heirarchy among its peers only. 
> That is to say, the sort-order tag should be added
> like this:
> 
> <Data>
> 	<Scope id="1" sort-order="1">
> 		<Scope id="2" sort-order="1"/>
> 		<Scope id="3" sort-order="2"/>
> 	</Scope>
> 	<Scope id="4" sort-order="2">
> 		<Scope id="5" sort-order="1">
> 			<Scope id="6" sort-order="1"/>
> 			<Scope id="7" sort-order="2"/>
> 		</Scope>
> 		<Scope id="8" sort-order="2">
> 			<Scope id="9" sort-order="1">
> 				<Scope id="10" sort-order="1"/>
> 				<Scope id="11" sort-order="2"/>
> 			</Scope>
> 			<Scope id="12" sort-order="2"/>
> 		</Scope>
> 	</Scope>
> 	<Scope id="13" sort-order="3"/>
> </Data>

  <xsl:template match="Scope">
    <xsl:copy>
      <xsl:attribute name="sort-order">
        <xsl:number />
      </xsl:attribute>
      <xsl:apply-templates select="@* | node()"/>
    </xsl:copy>
  </xsl:template>
  <xsl:template match="@* | node()">
    <xsl:copy>
      <xsl:apply-templates select="@* | node()"/>
    </xsl:copy>
  </xsl:template>

If you want to specify the attributes in xsl:number, they're

  <xsl:number level="single" count="Scope" from="Scope"/>

Cheers,

Jarno - Velvet Acid Christ: The Dead (Alive mix by Funker Vogt))