RE: [xsl] passing a node name as a param and then using it

Subject: RE: [xsl] passing a node name as a param and then using it
From: "Josh Canfield" <Josh.Canfield@xxxxxxxxxxxx>
Date: Wed, 16 Jun 2004 11:36:05 -0700
This question has been asked a couple of times today, and yesterday.

The short answer is, you're right, <xsl:value-of select="'string'"/> does indeed output the value of the string. You want to look for an extension function called evaluate, which will evaluate that string as an xpath expression.

http://www.google.com/search?hl=en&ie=UTF-8&q=exslt+evaluate&btnG=Google+Search

Josh

-----Original Message-----
From: Mike Kellstrand [mailto:kellstrand@xxxxxxxxx]
Sent: Wednesday, June 16, 2004 11:29 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] passing a node name as a param and then using it


I want to be able to pass a node name into a named
template as a param and
then operate on it.  When I try to use the node name
param in the template, 
it gets interpreted as a string and not an actual
node.   i.e.
 
The snipett:
<xsl:variable name="x" select="choice"/>
<fo:block>a: <xsl:value-of
select="choice[1]"/></fo:block>
<fo:block>b: <xsl:value-of
select="concat($x,'[1]')"/></fo:block>
 
Will generate:
a: {the actual xml data in the 1st choice node}
b: choice[1]
 
How do I get this to work as intended?
 
Thanks,  Mike


		
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