Subject: RE: [xsl] Output character references for all but one character From: "Michael Kay" <mhk@xxxxxxxxx> Date: Mon, 21 Jun 2004 19:23:54 +0100 |
> Consider the following xml: > > <node value="£">Hello World</node> > > I have the problem where I need characters outside the ascii > range to be output as references, apart from the pound sign, > which must remain as the actual character. I don't understand. You want the output to be ASCII, but you want the # sign output as a hex A3 byte? Those are surely contradictory requirements. Michael Kay > > The processor is Saxon 7.8 and is fixed. I can't use d-o-e > as the pound sign is always an attribute value, and saxon 7.8 > no longer supports d-o-e on attributes in favour of character > maps. When I use the following stylesheet, I get a '?' > character instead of the the pound, I guess because Saxon > can't output the pound sign because it's not in the ascii range... > > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > xmlns:saxon="http://saxon.net.sf/" > exclude-result-prefixes="saxon"> > > <xsl:output method="xhtml" encoding="ascii" > omit-xml-declaration="yes" use-character-maps="style"/> > > <xsl:character-map name="style"> > <xsl:output-character character="£" string="£"/> > </xsl:character-map> > > <xsl:template match="@*|node()"> > <xsl:copy> > <xsl:apply-templates select="@*|node()"/> > </xsl:copy> > </xsl:template> > > </xsl:stylesheet> > > Outputs: > > <node value="?">Hello World</node> > > I'm really after an exact copy of the input: > > <node value="£">Hello World</node> > > Any ideas? > > cheers > andrew > > --+------------------------------------------------------------------ > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/ > or e-mail: <mailto:xsl-list-unsubscribe@xxxxxxxxxxxxxxxxxxxxxx> > --+-- > >
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