Subject: Add products of two recursive additions From: "James Steven" <JSteven@xxxxxxxxxxxxxxxxxxxxx> Date: Tue, 22 Jun 2004 12:16:46 +0100 |
Hello I have two recursive addition functions producing totals which I would like to add together. How can I do this? Eg To produce the first total I have used the xsl shown below: <xsl:template match="a"> <xsl:call-template name="orderlist.sum.edit"> <xsl:with-param name="set-of-order" select="b/c"/> </xsl:call-template> </xsl:template> The call-template above calls the template below to display the total for 'data': <xsl:template name="orderlist.sum.edit"> <xsl:param name="set-of-order"/> <xsl:variable name="sumorg"> <xsl:call-template name="orderlist.sum"> <xsl:with-param name="set-of-order" select="$set-of-order"/> </xsl:call-template> </xsl:variable> <xsl:value-of select='format-number($sumorg, "£###,###,##0.00")'/> </xsl:template> <xsl:template name="orderlist.sum"> <xsl:param name="set-of-order"/> <xsl:choose> <xsl:when test="$set-of-order"> <xsl:variable name="first"> <xsl:apply-templates select="$set-of-order[1]/data"/> </xsl:variable> <xsl:variable name="rest"> <xsl:call-template name="orderlist.sum"> <xsl:with-param name="set-of-order" select="$set-of-order[position() != 1]"/> </xsl:call-template> </xsl:variable> <xsl:value-of select="$first + $rest"/> </xsl:when> <xsl:otherwise>0</xsl:otherwise> </xsl:choose> </xsl:template> The second total is acquired in the same way. An example of the xml I am using is also shown below: <a> <b> <c> <data>1</data> </c> <c> <data>3</data> </c> <d> <data>1</data> </d> <d> <data>5</data> </d> <d> <data>2</data> </d> </b> </a> The two call-templates above refering to the recursive addition functions produce the totals for <data> in <c> as 5 and <d> as 7. How do I obtain 12 as the total of both? Thankyou very much for your help.
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