Re: [xsl] Find attribute of node derived from extended base of ComplexType

["G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>]

At 2004-06-24 00:27 +0200, xdevpj@xxxxxx wrote:
> I want to know wheter or not an ancester of a node has an attribute 
> maxOccurs and the value of this attribute.
>
> For nodes like the countries in the example below this is no problem with:
>
> <xsl:when test="ancestor::*/@maxOccurs">
>         <xsl:value-of select="ancestor::*/@maxOccurs"/>
> </xsl:when>
>
> I get the '3' of the node <xs:element name="ACountry" minOccurs="0" 
> maxOccurs="3">.
>
>
> The question now is:
> How do I find the attribute and get the 'unbounded' value of the element:
>         <xs:element name="AnEntry" type="AnEntryType" maxOccurs="unbounded"/>

You don't say if you are using XSLT 1.0, but I'll assume you are.

> when the current node is i.e:
> <xs:element name="ANumber"> of the extended base of the complexType 
> "AnEntryType"?

XPath 1.0 delivers specified attributes from the start tags and defaulted 
attributes from an XML 1.0 DTD.  XPath 1.0 knows nothing about W3C Schema.

> Any Ideas?

I'm working with Universal Business Language (UBL) Schemas that are written 
in W3C Schema and they have defaulted attributes as well ... and I'm using 
XSLT/XPath 1.0 so I'm faced with the same problem you have.

I run my XML instances through the Xerces DOMPrint sample application 
before applying the XSLT/XPath 1.0 stylesheet.  This utility will output an 
XML document complete with W3C Schema defaulted attributes for the input 
XML document.

There is a W3C schema for W3C schemas, so I suspect if you ran your schema 
through DOMPrint you would end up with a "fleshed-out" schema complete with 
defaulted attributes from the schema for schemas, and then you can run your 
XSLT/XPath 1.0 stylesheet against that output instance.

I hope this helps.

........................... Ken

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