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Subject: RE: [xsl] Wildcards in namespaces ? From: "Michael Kay" <mhk@xxxxxxxxx> Date: Thu, 1 Jul 2004 12:56:17 +0100 |
XPath 2.0 allows constructs of the form *:local which will match local in
any namespace, but there's no way of matching a set of namespaces.
I would recommend using a first transformation pass to normalize the
namespace URI, to keep this separate from the "real" transformation logic.
This is just a variant on the identity template:
<xsl:template match="one-uri:*">
<xsl:element name="{local-name}" namespace="two-uri">
<xsl:copy-of select="@*"/>
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
Michael Kay
> -----Original Message-----
> From: Mick Baggen [mailto:mick.baggen@xxxxxxxxxxxxxxx]
> Sent: 01 July 2004 08:30
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Wildcards in namespaces ?
>
> Hello,
>
> I would appreciate some help with the following problem:
>
> I'm writing a XSLT stylesheet for processing of UML XMI files. Alas,
> depending on the UML tool, the elements in the XMI file are
> placed in a
> different namespace. E.g. Poseidon (www.gentleware.com) uses the
> namespace-URI xmlns:UML = "org.omg.xmi.namespace.UML", and
> Rational Rose
> uses xmlns:UML = "href://org.omg/UML/1.3". However, all of
> them generate a
> prefix UML: for their XMI elements.
>
> Now my problem is: how can I define a namespace in my XSLT
> stylesheet so
> that I can process all XMI files with the SAME stylesheet ? I
> came across a
> remark on the XSLT FAQ suggesting that it is possible to use
> wildcards in
> the namespace, eg <xsl:stylesheet xmlns:UML="*UML*">. And
> indeed, it seems
> that Xalan 2.6.0 recognizes this notation. However, libxslt 1.1.6
> (xmlsoft.org) does not.
>
> I tried to look it up in the XSLT and XML Namespace
> specifications, but I
> couldn't find whether this is valid. Could someone help me
> out on this one ?
> If it is NOT valid XSLT, is there another way to achieve the
> same result ?
>
> Regards,
>
> Mick Baggen
> Principal Consultant
> Technolution B.V.
> E-mail: mick.baggen@xxxxxxxxxxxxxxx
>
>
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