Re: [xsl] How to find out number of elements which does not have a particular attribute

[Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>]

Ranjan,

But I'm not sure this is going to work (have you tested it?):

count(connectivity//*[@*[not(local-name() = 'sharedsource')]])

for the stated requirement

> how to find out [the] number of elments which [do] not have a particular 
> attribute?

Parsing the XPath into English ...

count()
  counts a set of nodes

connectivity
  expands to child::connectivity ('connectivity' child elements of the 
context node) ... this could be what you want, depending on the input and 
the context node being matched

connectivity//*
  expands to child::connectivity/descendant-or-self::node()/*
  namely any element descendant of the 'connectivity' children

[@*]
  "which has an attribute"

[not(local-name() = 'sharedsource')]
  "whose local name is not 'sharedsource'"

In other words, the expression returns the count of all descendants of 
'connectivity' children that have an attribute whose local name is not 
'sharedsource'.

This is different from all elements that have no 'sharedsource' attribute.

To cut to the chase, the latter would be

count(//*[not(@sharedsource)])

which returns the count of all element descendants of the root that have no 
'sharedsource' attribute.

Its long-syntax form is

count(/descendant-or-self::node()/*[not(attribute::sharedsource)])

Cheers,
Wendell

At 08:36 AM 7/7/2004, 'twas written:
> > <xsl:variable name="sharedcount1"
> > select="count(connectivity//*[@*[not(local-name() =
> > 'sharedsource')]])"/>


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