Subject: Re: [xsl] position() in xsl:for-each From: George Cristian Bina <george@xxxxxxx> Date: Fri, 09 Jul 2004 15:06:17 +0300 |
> Ah. That explains everything. > > I think I'll copy the <object>s of the correct @type into another > tree, and then use this tree to output the table correctly. > > That is, if there's no simpler solution :)
Best Regards, George ----------------------------------------------- George Cristian Bina <oXygen/> XML Editor & XSLT Editor/Debugger http://www.oxygenxml.com
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