Subject: RE: [xsl] parsing string or numbers after x characters From: <Jarno.Elovirta@xxxxxxxxx> Date: Tue, 13 Jul 2004 10:24:05 +0300 |
Hi, > I'm quite new to the xsl mailing list so I have no idea if > this problem > occurred already and I was unable to find the solution on the web. > > My problem is that I receive for example a date in a > concatenated format: > > Ex: 20041207 > > And I have to retrieve it in a readable format through my xslt-fo > transformation. > > Ex. 12 July 2004 > > I tried using the substring attribute for that, but I don't have any > reference character to look at so it doesn't work. Is there a > function > which parses strings or numbers after a certain amount of characters > directly? Substring function <http://www.w3.org/TR/xpath#function-substring>. concat(substring(., 5, 2), ' ', substring('JanFebMarAprMayJunJulAugSepOctNovDec', substring(., 7, 2) * 3 - 2, 3), ' ', substring(., 1, 4)) will give you "12 Jul 2004", but for complete month names concat(substring(., 5, 2), ' ', document('')/*/x:months/month[position() = substring(current(), 7, 2)], ' ', substring(., 1, 4)) with a top level element <x:months> <month>January</month> <month>February</month> <month>March</month> ... </x:months> Cheers, Jarno - Delerium: After All (Svenson & Gielen Remix)
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