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Re: [xsl] node's full content + some modifications in that

Subject: Re: [xsl] node's full content + some modifications in that
From: "Földényi Tamás" <ftomi@xxxxxxx>
Date: Thu, 22 Jul 2004 00:54:25 +0200
Thanks, Mukul! It works great! :)

>   Please try this XSL -
> 
> <?xml version="1.0" encoding="ISO-8859-1"?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
> 
> <xsl:output method="html" indent="yes"/>
> 
> <xsl:template match="/">
>   <html>
>     <body>
>       <table>
> <xsl:for-each select="catalog/cd">
>   <tr>
>     <td>
>       <xsl:apply-templates select="artist"/>
>     </td>
>   </tr>
> </xsl:for-each>
>       </table>
>     </body>
>   </html>
> </xsl:template>
> 
> <xsl:template match="artist">
>   <xsl:apply-templates />
> </xsl:template>
> 
> <xsl:template match="tab">
>   <xsl:text>&#xA0;</xsl:text>
> </xsl:template>
> 
> <xsl:template match="*[(name() != 'artist') and
> (name() != 'tab')]">
>    <xsl:element name="{name()}">
>      <xsl:apply-templates />
>    </xsl:element>
> </xsl:template> 
> 
> </xsl:stylesheet>
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