RE: [xsl] using exsl:node-set()

You mean exslt.org, I think.

The node-set() function cannot be implemented using XSLT itself, it has to
be implemented by the vendor. All XSLT implementations that I know of
provide such a function, but it's sometimes in the vendor's namespace rather
than the EXSLT namespace.

Michael Kay 

> -----Original Message-----
> From: Markus Hanel [mailto:markus.hanel@xxxxxx] 
> Sent: 26 July 2004 10:58
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] using exsl:node-set()
> 
> hallo,
> I make something wrong! I want to use the exsl:node-set() 
> function but at
> www.exsl.org there is no download of the exsl.node-set.xsl 
> stylesheet. But
> in the main download there are two stylesheets: 
> exsl.node-set.1.xsl and
> exsl.node-set.2.xsl, but this not works.
> 
> markus
> 
> <?xml version="1.0" encoding="iso-8859-1"?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
> xmlns:exsl="http://exslt.org/common"; 
> extension-element-prefixes="exsl">
> 
> <xsl:import href="exsl.node-set.1.xsl" />
> <xsl:import href="exsl.node-set.2.xsl" />
> 
> <xsl:template match="/">
> <html>
> <head><title></title></head>
> 
> <body>
>   <xsl:apply-templates select="./table" />
> </body>
> </html>
> </xsl:template>
> 
> <xsl:template match="table">
> <xsl:variable name="sorted-rows-rtf">
>     <xsl:for-each select="./row">
>       <xsl:sort select="sum(./cell/@points)" data-type="number"
> order="descending" />
>       <xsl:copy-of select="." />
>     </xsl:for-each>
>   </xsl:variable>
> 
>   <xsl:variable name="sorted-rows"
> select="exsl:node-set($sorted-rows-rtf)/row" />
>   <xsl:value-of select="sum($sorted-rows[position() &lt;= 
> 4]/cell/@points)"
> />
> </xsl:template>
> </xsl:stylesheet>

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