Re: [xsl] Select parent node

["Vasu Chakkera" <vasucv@xxxxxxxxxxx>]

you could do this is in a couple of ways..

do
select="icon[icon_nr = 2]/@id"
select="icon[icon_nr = 2]/icon_title"

or
Define a key..and use it..
like

<xsl:key match = "/icon" name = "icons" use = "icon_nr"/>
as a child of the xsl:stylesheet


and then in your template,
use
select="key('icons',1)/@id"
select="key('icons',2)/icon_title"

Vasu



----- Original Message ----- 
From: "Bart Claeys" <Bart.Claeys@xxxxxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Monday, July 26, 2004 9:58 AM
Subject: [xsl] Select parent node


> Hi there!
>
> I've got this, (probably simple) question selecting only one specific
node. Consider the following XML structure, how can I
> retrieve the values of the node where icon_nr = 2. I want to retrieve the
icon's ID and the icon_title.
>
> <icon id="2343">
> <icon_nr>1</icon_nr>
> <icon_title>Yesterday</icon_title>
> </icon>
> <icon id="3432">
> <icon_nr>2</icon_nr>
> <icon_title>Today</icon_title>
> </icon>
> <icon id="1023">
> <icon_nr>3</icon_nr>
> <icon_title>Tomorrow</icon_title>
> </icon>
>
>
> Thanks a lot!
> Grtz, Bart
>
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