Re: [xsl] can you select name() of attributes?

["Ragulf Pickaxe" <jawxml@xxxxxxxxxxx>]

Hi David,

I got somewhat the same solution, but then I run into a different problem, 
which is why I want to use it as a nodeset. The ones in the input document 
(let us say $ Doc1) must be in $Doc2, but if they are not in $Doc1, then the 
(default) value in $Doc2 should be used.


> <xsl:variable name="Attr1" select="$Doc1/@*"/>
> <xsl:variable name="Attr2" select="$Doc2/@*"/>

<xsl:for-each select="$Attr2">
 <xsl:variable name="Attr" select="."/>
   <xsl:if test="not($Attr1)">
     <xsl:attribute name="{name($Attr)}"><xsl:value-of 
select="$Attr"/></xsl:attribute>
   </xsl:if>
 <xsl:for-each select="$Attr1[name()=name($Attr)]">
   <xsl:choose>
     <xsl:when test="name()=name($Attr)">
       <xsl:attribute name="{name(.)}"><xsl:value-of 
select="."/></xsl:attribute>
     </xsl:when>
     <xsl:otherwise>
       <xsl:attribute name="{name($Attr)}"><xsl:value-of 
select="$Attr"/></xsl:attribute>
     </xsl:otherwise>
   </xsl:choose>
 </xsl:for-each>
</xsl:for-each>

This works if there are no attributes in $Doc1 (if-sentence takes care of 
that) but if some of the attributes are in $Doc1, then the attributes - by 
nature of being nested in two for-each loops - will be overwritten (same 
name), ending in the last iteration creating the output.

Is there something else I can do?

Unfortunately I do not have access to a version which uses XSLT2, and I do 
not know if MK's solution would work in my case anyway (same problem as 
above).

Thank you for your time
Ragulf Pickaxe :-)

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