Re: [xsl] using traslate function to replace strings

Subject: Re: [xsl] using traslate function to replace strings
From: kotes mog <kotesm@xxxxxxxxx>
Date: Fri, 13 Aug 2004 12:11:40 -0700 (PDT)
Marina,

Thanks for the help. The "replace-string" template
available in FAQ has solved the problem.

Thanks
Kotes


--- Marina Cuello <cuello@xxxxxxxxxxxxxx> wrote:

> >                 <xsl:value-of
> select="concat($cutA,'dependency'.$cutB)"/>
> 
> I'm sorry, it's "concat($cutA,'dependency',$cutB)"
>           
> Marina
> 
> 



	
		
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