Re: [xsl] Multiple matches against keys?

["Ramon M. Felciano @ Yahoo" <felciano@xxxxxxxxx>]

Kevin Jones wrote:

> > So it looks like my key definition is no longer picking up "call" as a
> > valid key item. I'm actually not sure whether I'm using the <xsl:key>
> > tag correctly here -- will it match and index a single <task> node
> > multiple times if it contains multiple tags?
> >
> >    
>
> I think your problem is that you are passing a nodeset to the key call so that 
> it retruns results from different 'context' sets. This means you can't use 
> the count(.|key(...)[1])=1 trick to isolate the first from a particular 
> 'context'.  One way to fix is is to loop both over the 'task' and then the 
> child 'context' elements and apply the same test. Something like this should 
> work,
>
> <xsl:for-each select="/tasks/task">
> <xsl:sort select="subject"/>
> <xsl:for-each select="context">
>  <xsl:if test="count((..|key('tasks-by-context',.)[1]))=1">
>   <li>
>    CONTEXT: <xsl:value-of select="."/>: (<xsl:value-of
> 	select="count(key('tasks-by-context',.))"/> tasks)
>   </li>
>   <ul>
>    <xsl:for-each select="key('tasks-by-context', .)">
>     <li>
>       Task : <xsl:value-of select="subject"/>
>     </li>
>    </xsl:for-each>
>   </ul>
>  </xsl:if>
> </xsl:for-each>
> </xsl:for-each>
>
> Kev.
Hi Kev --

This is almost right -- it gives me the right grouping, but the sort 
order is wrong. How can I get that outer loop to sort the contexts 
alphabetically? Do I need to make the outer loop iterate over the sorted 
contexts first?

Thanks!

Ramon