Re: [xsl] getting position of tag

[Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>]

Hi Dusan,

You don't really want "position()", which returns the position of the 
current node in the current node list. You haven't shown us what your 
template is matching here, so we don't know what either of those are, but 
it's not really a relevant question, since your XPath, which traverses from 
the root, suggests you want this number irrespective of the processing context.

Accordingly, you can do one of two things:

1. Count the columns preceding the column you want, and add 1:

xsl:value-of
 select="count(/columns/column[source='B']/preceding-sibling::column) + 1"

2. Change context to the column you want, and use the xsl:number instruction

<xsl:for-each select="/columns/column[source='B']">
  <xsl:number/>
</xsl:for-each>

(If you are in a template that has matched this node, the for-each 
instruction is unnecessary.)

Look up xsl:number to learn about its many powerful and useful features.

I hope that helps,
Wendell

At 09:55 AM 9/15/2004, you wrote:
> Hi.
>
> I have this problem:
>
> XML:
> <columns>
>         <column>
>                 <source>A</source>
>         </column>
>         <column>
>                 <source>B</source>
>         </column>
> </xolumns>
>
> I want to get position() of tag column, where source='B'.
>
> I have tried
> xsl:value-of select="/columns/column[source='B']/position()"
> but it is bad.
>
> Anyone help me?

======================================================================
Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
Mulberry Technologies, Inc.                http://www.mulberrytech.com
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Suite 207                                          Phone: 301/315-9631
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