Re: [xsl] problem with table

["G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>]

At 2004-09-20 15:21 +0530, Eldho George wrote:
> I have some problem with <fo:table-column>.Suppose i am using different
> table structure such as
> first <tr> contains 3 <td>.Second <tr> contains 4 <td>.Then 3<tr> onwards it
> contains 6 <td>
> The following is my table template.
> <xsl:for-each select="tr/th|tr/td|thead/tr/th|thead/tr/td">
>         <fo:table-column/>
> </xsl:for-each>

This would obtain *every* th and *every* td and give you one table column 
per item, which is why you are getting so many columns.

Remember that all rows in an XSL-FO table will render with the same number 
of columns and the column edges will be the same for all rows in a single 
table.

Thus, you need only traverse the maximum number of columns.  The maximum 
number of columns can be obtained by sorting the rows by the number of 
columns, sorting them in descending order, and acting on the first of those:

      <xsl:for-each select="tr|thead/tr">
        <xsl:sort select="count(td|th)" data-type="number"
                  order="descending"/>
        <xsl:if test="position()=1">
          <xsl:for-each select="td|th">
            <table-column/>
          </xsl:for-each>
        </xsl:if>
      </xsl:for-each>

I hope this helps.

............................ Ken




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