RE: [xsl] How to sort?

[<Jarno.Elovirta@xxxxxxxxx>]

Hi,

> What I do now, is choose all Article elements that contain info="main"
> and info="sub" attributes and then sort everything by state="n"
> attribute.

An Article cannot have two info attributes, thus the above condition can never
be true in XML.

> Is it possible to implement an sorting option that enables Article
> elements where filter="food" to be placed on the top of the Article
> list, that is giving them higher priority in sort than the previous
> value of state="n".
>
> so the XML output will look like:
>
> <?xml version="1.0"?>
> <Documents>
> 	<Document title="1" chapter="i" href="file1.xml" filter="food">
> 		<Article title="1.2" info="main" filter="food"/>
> 		<Article title="1.3" info="main" filter="drink"
> state="2"/>
> 	</Document>
>
> 	<Document title="2" chapter="ii" href="file2.xml"
> filter="drink">
>     	               <Article title="2.2" info="main" filter="food"/>
>     	               <Article title="2.1" info="main"
> filter="drink" state="1"/>
> 	</Document>
>
> 	<Document title="4" chapter="2" href="file2.xml" filter="">
> 		<Article title="3.2" info="main" filter="food"/>
> 	</Document>
> </Documents>

  <xsl:template match="Documents">
    <xsl:copy>
      <xsl:apply-templates select="Document[Article/@info = 'main' and
Article/@info = 'sub']"/>
    </xsl:copy>
  </xsl:template>
  <xsl:template match="Document">
    <xsl:copy>
      <xsl:copy-of select="@*"/>
      <xsl:for-each select="Article[@info = 'main']">
        <xsl:sort select="@filter ='food'" data-type="number"
order="descending"/>
        <xsl:sort select="@state" data-type="number"/>
        <xsl:copy-of select="."/>
      </xsl:for-each>
    </xsl:copy>
  </xsl:template>

I'm not sure exactly how you wanted the info attribute handled, because you
desired output doesn't use Articles with "sub" info. Anyhow, this produces the
desired output. The

  <xsl:sort select="@filter ='food'" data-type="number" order="descending"/>

sort condition basically works so that the "@filter = 'food'" expression will
either return boolean true or false, which will be cast to number 1 or 0,
respectively, and that gives you the sort key value.

Cheers,

Jarno - Lisa Lashes: Hard Mix