Subject: Re: [xsl] ancestor From: David Carlisle <davidc@xxxxxxxxx> Date: Mon, 18 Oct 2004 17:10:52 +0100 |
select="//inlineequation[not (ancestor::* = 'table')]" that tests if the string value of each ancestor (ie the concatenation of all the character data in all the descendants of each ancestor) is the string table. You want to know if the inlineequation has a table ancestor so that would be select="//inlineequation[not (ancestor::table)]" The // of course means search the whole document which is expensive but if that's what you need to do, that's what you need to do. (If you need to do it more than once, use a xsl:key to optimise that) David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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