Subject: Re: [xsl] how to store node in variable? From: "Joe Fawcett" <joefawcett@xxxxxxxxxxx> Date: Thu, 21 Oct 2004 21:16:30 +0100 |
Sorry to trouble the list with this one which seems so simple and yet somehow I am banging my head against the wall for hours and I can't even think what to search for. The worst part is I think I've done this before...In XSLT 1 I believe you need to covert $me to a node-set using an extension function. In version 2 you can use the variable directly or simplify the code to use an XPtah expression like "if <some condition> then . else .."
How do I store a reference to a node in a variable or what am I doing wrong? Here is what I have (maybe oversimplified) :
<xsl:variable name="me"> <xsl:choose> <xsl:when test="<some condition>"> <xsl:copy-of select=".." /> </xsl:when> <xsl:otherwise> <xsl:copy-of select="." /> </xsl:otherwise> </xsl:choose> </xsl:variable> <xsl:call-template name="<some template>"> <xsl:with-param name="myid" select="$me/@id" /> </xsl:call-template>
The with-param is always throwing an error, expression should result in a node-set.
If I add msxsl:node-set around my selects in the variable definition I get cannot convert result tree fragment to node-set.
Alternatively, is there any way to explicitly set the context node without using for-each?
Again my apologies.
-John
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