Re: [xsl] Applying Templates to a Substring

["G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>]

At 2004-10-21 14:20 -0400, Joe Heidenreich wrote:
> If I have a <li> node like this:
>
> <ol>
>      <li>1) This is the <b>first</b> item.</li>
>      <li>2) This is the 2<sup>nd</sup> item.</li>
> </ol>
>
> and I want the output to be:
>
> <ol>
>      <li>This is the <b>first</b> item.</li>
>      <li>This is the 2<sup>nd</sup> item.</li>
> </ol>
>
> However I'm not aware of how you can apply-templates to a substring.

You cannot.

> The only way I can get the proper substring I need that I know of is:
>
> <xsl:value-of select="substring-after(.,')')"/>

But you didn't think to do it at the text node level.

Attached below are two examples, joe1.xsl and joe2.xsl ... use joe1.xsl if 
the first parenthesis pattern in the list item is never going to be, 
itself, in markup (typical).  Use the more elaborate joe2.xsl if the first 
parenthesis pattern in the list item can be at any level of the subtree 
under the <li>  (which it shouldn't be from your sample, but this technique 
I've used is useful for things like drop-initial-caps that might be in 
markup; I've added border cases to the joe.xml sample).

I hope this helps.

.................. Ken

T:\ftemp>type joe.xml
<ol>
     <li>1) This is the <b>first</b> item.</li>
     <li>2) This is the 2<sup>nd</sup> item.</li>
     <li>1) This is the <b>1) first</b>1) item.</li>
     <li>2) This is the 2<sup>nd</sup> item.</li>
     <li><b>3) </b>Third</li>
</ol>
T:\ftemp>type joe1.xsl
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
                version="1.0">

<xsl:template match="li//text()[1]">
  <xsl:choose>
    <xsl:when test="contains(.,') ')">
      <xsl:value-of select="substring-after(.,') ')"/>
    </xsl:when>
    <xsl:otherwise>
      <xsl:value-of select="."/>
    </xsl:otherwise>
  </xsl:choose>
</xsl:template>

<xsl:template match="@*|node()"><!--identity for all other nodes-->
  <xsl:copy>
    <xsl:apply-templates select="@*|node()"/>
  </xsl:copy>
</xsl:template>

</xsl:stylesheet>
T:\ftemp>saxon joe.xml joe1.xsl
<?xml version="1.0" encoding="utf-8"?><ol>
     <li>This is the <b>first</b> item.</li>
     <li>This is the 2<sup>nd</sup> item.</li>
     <li>This is the <b>first</b>1) item.</li>
     <li>This is the 2<sup>nd</sup> item.</li>
     <li><b/>Third</li>
</ol>
T:\ftemp>type joe2.xsl
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
                version="1.0">

<xsl:template match="li//text()[1]">
  <xsl:choose>
    <xsl:when test="ancestor-or-self::node()[not(descendant-or-self::li)]/
                    preceding-sibling::node() or
                    not(contains(.,') '))">
      <xsl:value-of select="."/>
    </xsl:when>
    <xsl:otherwise>
      <xsl:value-of select="substring-after(.,') ')"/>
    </xsl:otherwise>
  </xsl:choose>
</xsl:template>

<xsl:template match="@*|node()"><!--identity for all other nodes-->
  <xsl:copy>
    <xsl:apply-templates select="@*|node()"/>
  </xsl:copy>
</xsl:template>

</xsl:stylesheet>
T:\ftemp>saxon joe.xml joe2.xsl
<?xml version="1.0" encoding="utf-8"?><ol>
     <li>This is the <b>first</b> item.</li>
     <li>This is the 2<sup>nd</sup> item.</li>
     <li>This is the <b>1) first</b>1) item.</li>
     <li>This is the 2<sup>nd</sup> item.</li>
     <li><b/>Third</li>
</ol>
T:\ftemp>


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