Subject: Re: [xsl] Detecting item types within a sequence (XSLT2.0/XPath2.0) From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 28 Oct 2004 16:31:50 +0100 |
<?xml version="1.0"?> <xsl:stylesheet version="2.0" exclude-result-prefixes="xs" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xsl:template match="/"> <xsl:variable name="foo"> <aaa>aaa</aaa> <aaa>bbb</aaa> </xsl:variable> <xsl:variable name="bar" select="(xs:date('2004-10-30'), 1.1, 'A', $foo/*)"/> <output> <xsl:for-each select="$bar"> <xsl:variable name="this" select="."/> <xsl:text> Item </xsl:text> <xsl:value-of select="position()"/> <xsl:text> </xsl:text> <xsl:choose> <xsl:when test=". instance of xs:integer">integer</xsl:when> <xsl:when test=". instance of xs:date">date</xsl:when> <xsl:when test=". instance of xs:decimal">decimal</xsl:when> <xsl:when test=". instance of xs:string">string</xsl:when> <xsl:when test=". instance of element()">element</xsl:when> <xsl:otherwise>something else</xsl:otherwise> </xsl:choose> </xsl:for-each> <xsl:text> </xsl:text> </output> </xsl:template> </xsl:stylesheet> $ saxon8 type.xsl type.xsl <?xml version="1.0" encoding="UTF-8"?><output> Item 1 date Item 2 decimal Item 3 string Item 4 element Item 5 element </output> ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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