Subject: RE: [xsl] counting equal entries From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Fri, 29 Oct 2004 15:05:32 +0100 |
A classic grouping problem: see http://www.jenitennison.com/xslt/grouping Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Ralf Heydenreich [mailto:rheydenr@xxxxxxx] > Sent: 29 October 2004 13:53 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] counting equal entries > > Hi all, > I try to create an index page from a document. The idea behind is to > collect a certain word and list it with *all* occurences in the > document, like > > foo .... 12, 23, 45 > bar .... 2, 5, 88 > > and so on. I have a XML document which contains entries with different > classes (Java classes). > I have a XSL stylesheet which collects all entries in a sorted order. > But there is one separate entry for each occurence: > > foo ... 12 > foo ... 23 > foo ... 45 > bar ... 2 > > and so on. > > Code follows: > > <xsl:for-each select="key('index-key', $lower-alphabet)"> > <xsl:sort select="@name" case-order="lower-first"/> > <xsl:call-template name="display-index-item"> > <xsl:with-param name="item" select="." /> > </xsl:call-template> > </xsl:for-each> > > The $lower-alphabet is only a variable containing all lower letters. > How can I pass an indicator to the template "display-index-item" where > I can decide if an entry has the same name as the previous one? > > TIA, > Ralf.
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