RE: [xsl] "SQL distinct" like applying of templates

["Andrew Welch" <ajwelch@xxxxxxxxxxxxxxx>]

> Example:
> <list>
> 	<item>string1</item>
> 	<item>string2</item>
> 	<item>string2</item>
> 	<item>string3</item>
> </list>
>
> I want to get the following list, omitting the second node
> with the value "String2". string1 string2 string3

If you find grouping with XSLT 1.0 a bit heavy going, download Saxon and
use XSLT 2.0's grouping functionality:

  <xsl:for-each-group select="list/item" group-by=".">
     ...
  </xsl:for-each-group>

Easy, isn't it?  You may need to use Xpath 2.0's distinct-values()
function on the current-group(), depending on what you want to do inside
the loop.

cheers
andrew