RE: [xsl] <xsl:call-template> error

Subject: RE: [xsl] <xsl:call-template> error
From: Jen Jiang <zhenjiang14221@xxxxxxxxx>
Date: Fri, 5 Nov 2004 18:28:03 -0800 (PST)
I am sure they are in the save directory. I didn't
know RSS feed could be unavailable. I found that if I
run it on my local computer (Win XP)it worked but when
I upload the files onto a remote server which is a
Unix server it gives the error "Access denied" this
time. But I have changed the file permission to allow
read and execute. I'm so confused. Why does it have
different behavoirs when on different OS?

Thanks.



--- Pieter Reint Siegers Kort
<pieter.siegers@xxxxxxxxxxx> wrote:

> Hi again Jen,
> 
> I saved your XML as rss.xml, and your XSL as
> getRSS.xsl. 
> Then I loaded rss.xml in IE6 (using drag and drop
> from Windows Explorer to
> an IE window), and it seems to work fine as a series
> of links appear.
> 
> Are you sure your xml and xsl are in the same
> directory?
> Or the RSS feed wasn't available at the time you
> tried it?
> 
> Cheers,
> <prs/>
> 
> -----Original Message-----
> From: Jen Jiang [mailto:zhenjiang14221@xxxxxxxxx] 
> Sent: Friday, November 05, 2004 12:22 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: RE: [xsl] <xsl:call-template> error
> 
> It's IE6.
> 
> 
> Hi Jen,
> 
> Which browser do you use?
> 
> Cheers,
> <prs/> 
> 
> -----Original Message-----
> From: Jen Jiang [mailto:zhenjiang14221@xxxxxxxxx]
> Sent: Thursday, November 04, 2004 10:22 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] <xsl:call-template> error
> 
> I have an xml which is a RSS feed link:
> 
> <?xml-stylesheet href="getRSS.xsl" type="text/xsl"?>
> <RSSChannels>
> 
>   <!-- RSS 0.91 feeds -->
>   <RSSChannel
> src="http://www.tinnitus-research.org/atr.xml"/>
>   <!-- RSS 1.0 feeds -->
>   <!-- RSS 2.0 feeds -->
>   <RSSChannel
>
src="http://www.medicinenet.com/rss/specialty/Tinnitus.xml"/>
>   
> </RSSChannels>
> 
> I use an xslt file to transfer RSS to HTML:
> <?xml version="1.0"?>
> <!-- getRSS.xsl: retrieve RSS feed(s) and convert to
> HTML. -->
> <xsl:stylesheet
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
> xmlns:dc="http://purl.org/dc/elements/1.1/";
> version="1.0">
> 	<xsl:output method="html" encoding="iso-8859-1"/>
> 	<xsl:template match="RSSChannels">
> 		<html>
> 			<head>
> 				<title>Today's Headlines</title>
> 			</head>
> 			<body>
> 				<xsl:apply-templates/>
> 			</body>
> 		</html>
> 	</xsl:template>
> 	<xsl:template match="RSSChannel">
> 		<xsl:apply-templates select="document(@src)"/>
> 	</xsl:template>
> 	<!-- Named template outputs HTML a element with
> href link and RSS
>        description as title to show up in mouseOver
> message. -->
> 	<xsl:template name="a-element">
> 		<xsl:element name="a">
> 			<xsl:attribute name="href"><xsl:apply-templates
> select="*[local-name()='link']"/></xsl:attribute>
> 			<xsl:attribute name="title"><xsl:apply-templates
>
select="*[local-name()='description']"/></xsl:attribute>
> 			<xsl:value-of select="*[local-name()='title']"/>
> 		</xsl:element>
> 	</xsl:template>
> 	<!-- Output RSS channel name as HTML a link inside
> of
> h1 element. -->
> 	<xsl:template match="*[local-name()='channel']">
> 			<xsl:call-template name="a-element"/>
> 		<!-- Following line for RSS .091 -->
> 		<xsl:apply-templates
> select="*[local-name()='item']"/>
> 	</xsl:template>
> 	<!-- Output RSS item as HTML a link inside of p
> element. -->
> 	<xsl:template match="*[local-name()='item']">
> 			<xsl:call-template name="a-element"/>
> 			<xsl:text> </xsl:text>
> 			<xsl:if test="dc:date">
> 				<!-- Show date if available -->
> 				<xsl:text>( </xsl:text>
> 				<xsl:value-of select="dc:date"/>
> 				<xsl:text>) </xsl:text>
> 			</xsl:if>
> 	</xsl:template>
> </xsl:stylesheet>
> 
> But when I ran it in browser it gave me error: 
> 
> "The XML page cannot be displayed
> Cannot view XML input using XSL style sheet. Please
> correct the error and
> then click the Refresh button, or try again later. 
> 
> 
>
----------------------------------------------------------------------------
> ----
> 
> Keyword xsl:stylesheet may not contain
> xsl:call-template."
> 
> I don't know why this happened. I have used
> <xsl:call-template> in <xsl:stylesheet> so many
> times
> (not these files) without getting the error.
> 
> Thank you very much for any input.
> 
> 
> 
> 
> 
> 
> 
> 
> 
> 		
> __________________________________ 
> Do you Yahoo!? 
> Check out the new Yahoo! Front Page. 
> www.yahoo.com 
> 
> 



		
__________________________________ 
Do you Yahoo!? 
Check out the new Yahoo! Front Page. 
www.yahoo.com 

Current Thread