Re: [xsl] Identity Transform Grouping Question

[Geert Josten <Geert.Josten@xxxxxxxxxxx>]

ethan.kalfus@xxxxxxx wrote:

> 	<xsl:key name="offices" match="office" use="concat(cities/city[@lang='en'],'-',names/name[@lang='en'])"/>

...

> 	<!-- reorganize 'country' elements -->
> 	<xsl:template match="country">
> 		<country>
> 			<xsl:copy-of select="@*"/>
> 			<cities>
> 				<!-- group 'city' elements within this country -->
> 				<xsl:variable name="offices-in-this-country">
> 					<xsl:copy-of select="offices"/>
> 					<!-- this is a trick, to restrict all subsequent key usage to this country only -->
> 				</xsl:variable>
> 				<xsl:apply-templates select="msxsl:node-set($offices-in-this-country)/offices/office/cities[count(.|key('cities',city[@lang='en'])[1])=1]">
> 					<xsl:sort select="city[@lang='en']"/>
> 				</xsl:apply-templates>
> 			</cities>
> 		</country>
> 	</xsl:template>

Hi Ethan,

Why use the node-set function here if you could use a key as well?

<xsl:key name="offices-by-country" match="office" use="ancestor::country/@name"/>

Or am I missing something?

Grtz,
Geert