Subject: [xsl] Re: Problem passing node-set to params (RTF) From: Charlie Consumer <faceless1976@xxxxxxxxx> Date: Thu, 18 Nov 2004 07:01:31 -0800 (PST) |
Here is the original FAQ entry. I reread it, and I'm not sure if I misread it or not. The entry refers to "the contents of a variable." I'm not sure if this is accurate or just a funny way of saying it. It's not obvious to me. But, I fixed my problem. I was using two different variable names. So in my template I did this: <xsl:template name="foo"> <xsl:param name="srcNode"/> <xsl:param name="destNode"/> </xsl:template> And in my calls I was doing this: <xsl:call-template name="foo"> <xsl:with-param name="src" select="current()"/> <xsl:with-param name="dest" select="$local"/> </xsl:call-template> When I correctly assigned the variables to the defined parameters it work like a charm. I figured it was something stupid I was doing. :-) Thanks for the quick responses. Charlie http://www.dpawson.co.uk/xsl/sect2/N5982.html#d7429e172 __________________________________ Do you Yahoo!? The all-new My Yahoo! - Get yours free! http://my.yahoo.com
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